3(4x-1)=4(9-x)-7

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Solution for 3(4x-1)=4(9-x)-7 equation: 



3(4x-1)=4(9-x)-7

We move all terms to the left:

3(4x-1)-(4(9-x)-7)=0

We add all the numbers together, and all the variables

3(4x-1)-(4(-1x+9)-7)=0

We multiply parentheses

12x-(4(-1x+9)-7)-3=0



We calculate terms in parentheses: -(4(-1x+9)-7), so:

4(-1x+9)-7

We multiply parentheses

-4x+36-7

We add all the numbers together, and all the variables

-4x+29

Back to the equation:

-(-4x+29)



We get rid of parentheses

12x+4x-29-3=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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