3(4x-1)=6x+12

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Solution for 3(4x-1)=6x+12 equation:



3(4x-1)=6x+12
We move all terms to the left:
3(4x-1)-(6x+12)=0
We multiply parentheses
12x-(6x+12)-3=0
We get rid of parentheses
12x-6x-12-3=0
We add all the numbers together, and all the variables
6x-15=0
We move all terms containing x to the left, all other terms to the right
6x=15
x=15/6
x=2+1/2

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