3(4x-10)+8x=-80.

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Solution for 3(4x-10)+8x=-80. equation: 



3(4x-10)+8x=-80.

We move all terms to the left:

3(4x-10)+8x-(-80.)=0

We add all the numbers together, and all the variables

3(4x-10)+8x-(-80)=0

We add all the numbers together, and all the variables

8x+3(4x-10)+80=0

We multiply parentheses

8x+12x-30+80=0

We add all the numbers together, and all the variables

20x+50=0

We move all terms containing x to the left, all other terms to the right

20x=-50

x=-50/20

x=-2+1/2

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