3(4x-10)=-6(2x-5)+12

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Solution for 3(4x-10)=-6(2x-5)+12 equation: 



3(4x-10)=-6(2x-5)+12

We move all terms to the left:

3(4x-10)-(-6(2x-5)+12)=0

We multiply parentheses

12x-(-6(2x-5)+12)-30=0



We calculate terms in parentheses: -(-6(2x-5)+12), so:

-6(2x-5)+12

We multiply parentheses

-12x+30+12

We add all the numbers together, and all the variables

-12x+42

Back to the equation:

-(-12x+42)



We get rid of parentheses

12x+12x-42-30=0

We add all the numbers together, and all the variables

24x-72=0

We move all terms containing x to the left, all other terms to the right

24x=72

x=72/24

x=3

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