3(4x-2)+18=12(x+1)

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Solution for 3(4x-2)+18=12(x+1) equation: 



3(4x-2)+18=12(x+1)

We move all terms to the left:

3(4x-2)+18-(12(x+1))=0

We multiply parentheses

12x-(12(x+1))-6+18=0



We calculate terms in parentheses: -(12(x+1)), so:

12(x+1)

We multiply parentheses

12x+12

Back to the equation:

-(12x+12)



We add all the numbers together, and all the variables

12x-(12x+12)+12=0

We get rid of parentheses

12x-12x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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