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3(4x-2)+1=6(2x+3)-6
We move all terms to the left:
3(4x-2)+1-(6(2x+3)-6)=0
We multiply parentheses
12x-(6(2x+3)-6)-6+1=0
We calculate terms in parentheses: -(6(2x+3)-6), so:We add all the numbers together, and all the variables
6(2x+3)-6
We multiply parentheses
12x+18-6
We add all the numbers together, and all the variables
12x+12
Back to the equation:
-(12x+12)
12x-(12x+12)-5=0
We get rid of parentheses
12x-12x-12-5=0
We add all the numbers together, and all the variables
-17!=0
There is no solution for this equation
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