3(4x-2)+3x=6x+8-3x

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Solution for 3(4x-2)+3x=6x+8-3x equation:



3(4x-2)+3x=6x+8-3x
We move all terms to the left:
3(4x-2)+3x-(6x+8-3x)=0
We add all the numbers together, and all the variables
3(4x-2)+3x-(3x+8)=0
We add all the numbers together, and all the variables
3x+3(4x-2)-(3x+8)=0
We multiply parentheses
3x+12x-(3x+8)-6=0
We get rid of parentheses
3x+12x-3x-8-6=0
We add all the numbers together, and all the variables
12x-14=0
We move all terms containing x to the left, all other terms to the right
12x=14
x=14/12
x=1+1/6

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