3(4x-2)+4x=4(x-2)+14

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Solution for 3(4x-2)+4x=4(x-2)+14 equation:



3(4x-2)+4x=4(x-2)+14
We move all terms to the left:
3(4x-2)+4x-(4(x-2)+14)=0
We add all the numbers together, and all the variables
4x+3(4x-2)-(4(x-2)+14)=0
We multiply parentheses
4x+12x-(4(x-2)+14)-6=0
We calculate terms in parentheses: -(4(x-2)+14), so:
4(x-2)+14
We multiply parentheses
4x-8+14
We add all the numbers together, and all the variables
4x+6
Back to the equation:
-(4x+6)
We add all the numbers together, and all the variables
16x-(4x+6)-6=0
We get rid of parentheses
16x-4x-6-6=0
We add all the numbers together, and all the variables
12x-12=0
We move all terms containing x to the left, all other terms to the right
12x=12
x=12/12
x=1

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