3(4x-2)+4x=4(x-2)+14

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Solution for 3(4x-2)+4x=4(x-2)+14 equation: 



3(4x-2)+4x=4(x-2)+14

We move all terms to the left:

3(4x-2)+4x-(4(x-2)+14)=0

We add all the numbers together, and all the variables

4x+3(4x-2)-(4(x-2)+14)=0

We multiply parentheses

4x+12x-(4(x-2)+14)-6=0



We calculate terms in parentheses: -(4(x-2)+14), so:

4(x-2)+14

We multiply parentheses

4x-8+14

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

16x-(4x+6)-6=0

We get rid of parentheses

16x-4x-6-6=0

We add all the numbers together, and all the variables

12x-12=0

We move all terms containing x to the left, all other terms to the right

12x=12

x=12/12

x=1

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