3(4x-2)+7x=6(x+3)-2x-15

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Solution for 3(4x-2)+7x=6(x+3)-2x-15 equation: 



3(4x-2)+7x=6(x+3)-2x-15

We move all terms to the left:

3(4x-2)+7x-(6(x+3)-2x-15)=0

We add all the numbers together, and all the variables

7x+3(4x-2)-(6(x+3)-2x-15)=0

We multiply parentheses

7x+12x-(6(x+3)-2x-15)-6=0



We calculate terms in parentheses: -(6(x+3)-2x-15), so:

6(x+3)-2x-15

We add all the numbers together, and all the variables

-2x+6(x+3)-15

We multiply parentheses

-2x+6x+18-15

We add all the numbers together, and all the variables

4x+3

Back to the equation:

-(4x+3)



We add all the numbers together, and all the variables

19x-(4x+3)-6=0

We get rid of parentheses

19x-4x-3-6=0

We add all the numbers together, and all the variables

15x-9=0

We move all terms containing x to the left, all other terms to the right

15x=9

x=9/15

x=3/5

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