3(4x-2)-(7x-8)=40

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Solution for 3(4x-2)-(7x-8)=40 equation: 



3(4x-2)-(7x-8)=40

We move all terms to the left:

3(4x-2)-(7x-8)-(40)=0

We multiply parentheses

12x-(7x-8)-6-40=0

We get rid of parentheses

12x-7x+8-6-40=0

We add all the numbers together, and all the variables

5x-38=0

We move all terms containing x to the left, all other terms to the right

5x=38

x=38/5

x=7+3/5

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