3(4x-2)-1(-7x-8)=40

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Solution for 3(4x-2)-1(-7x-8)=40 equation:


Simplifying
3(4x + -2) + -1(-7x + -8) = 40

Reorder the terms:
3(-2 + 4x) + -1(-7x + -8) = 40
(-2 * 3 + 4x * 3) + -1(-7x + -8) = 40
(-6 + 12x) + -1(-7x + -8) = 40

Reorder the terms:
-6 + 12x + -1(-8 + -7x) = 40
-6 + 12x + (-8 * -1 + -7x * -1) = 40
-6 + 12x + (8 + 7x) = 40

Reorder the terms:
-6 + 8 + 12x + 7x = 40

Combine like terms: -6 + 8 = 2
2 + 12x + 7x = 40

Combine like terms: 12x + 7x = 19x
2 + 19x = 40

Solving
2 + 19x = 40

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 19x = 40 + -2

Combine like terms: 2 + -2 = 0
0 + 19x = 40 + -2
19x = 40 + -2

Combine like terms: 40 + -2 = 38
19x = 38

Divide each side by '19'.
x = 2

Simplifying
x = 2

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