3(4x-2)-10(2x-5)=4x+8

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Solution for 3(4x-2)-10(2x-5)=4x+8 equation: 



3(4x-2)-10(2x-5)=4x+8

We move all terms to the left:

3(4x-2)-10(2x-5)-(4x+8)=0

We multiply parentheses

12x-20x-(4x+8)-6+50=0

We get rid of parentheses

12x-20x-4x-8-6+50=0

We add all the numbers together, and all the variables

-12x+36=0

We move all terms containing x to the left, all other terms to the right

-12x=-36

x=-36/-12

x=+3

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