3(4x-2)-2=6(3x+1)-14

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Solution for 3(4x-2)-2=6(3x+1)-14 equation: 



3(4x-2)-2=6(3x+1)-14

We move all terms to the left:

3(4x-2)-2-(6(3x+1)-14)=0

We multiply parentheses

12x-(6(3x+1)-14)-6-2=0



We calculate terms in parentheses: -(6(3x+1)-14), so:

6(3x+1)-14

We multiply parentheses

18x+6-14

We add all the numbers together, and all the variables

18x-8

Back to the equation:

-(18x-8)



We add all the numbers together, and all the variables

12x-(18x-8)-8=0

We get rid of parentheses

12x-18x+8-8=0

We add all the numbers together, and all the variables

-6x=0

x=0/-6

x=0

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