3(4x-2)-5=6-7(-x-2)

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Solution for 3(4x-2)-5=6-7(-x-2) equation:



3(4x-2)-5=6-7(-x-2)
We move all terms to the left:
3(4x-2)-5-(6-7(-x-2))=0
We add all the numbers together, and all the variables
3(4x-2)-(6-7(-1x-2))-5=0
We multiply parentheses
12x-(6-7(-1x-2))-6-5=0
We calculate terms in parentheses: -(6-7(-1x-2)), so:
6-7(-1x-2)
determiningTheFunctionDomain -7(-1x-2)+6
We multiply parentheses
7x+14+6
We add all the numbers together, and all the variables
7x+20
Back to the equation:
-(7x+20)
We add all the numbers together, and all the variables
12x-(7x+20)-11=0
We get rid of parentheses
12x-7x-20-11=0
We add all the numbers together, and all the variables
5x-31=0
We move all terms containing x to the left, all other terms to the right
5x=31
x=31/5
x=6+1/5

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