3(4x-2)=4(3x-1)+1

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Solution for 3(4x-2)=4(3x-1)+1 equation:


Simplifying
3(4x + -2) = 4(3x + -1) + 1

Reorder the terms:
3(-2 + 4x) = 4(3x + -1) + 1
(-2 * 3 + 4x * 3) = 4(3x + -1) + 1
(-6 + 12x) = 4(3x + -1) + 1

Reorder the terms:
-6 + 12x = 4(-1 + 3x) + 1
-6 + 12x = (-1 * 4 + 3x * 4) + 1
-6 + 12x = (-4 + 12x) + 1

Reorder the terms:
-6 + 12x = -4 + 1 + 12x

Combine like terms: -4 + 1 = -3
-6 + 12x = -3 + 12x

Add '-12x' to each side of the equation.
-6 + 12x + -12x = -3 + 12x + -12x

Combine like terms: 12x + -12x = 0
-6 + 0 = -3 + 12x + -12x
-6 = -3 + 12x + -12x

Combine like terms: 12x + -12x = 0
-6 = -3 + 0
-6 = -3

Solving
-6 = -3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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