3(4x-20)=12(x-5)

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Solution for 3(4x-20)=12(x-5) equation:


Simplifying
3(4x + -20) = 12(x + -5)

Reorder the terms:
3(-20 + 4x) = 12(x + -5)
(-20 * 3 + 4x * 3) = 12(x + -5)
(-60 + 12x) = 12(x + -5)

Reorder the terms:
-60 + 12x = 12(-5 + x)
-60 + 12x = (-5 * 12 + x * 12)
-60 + 12x = (-60 + 12x)

Add '60' to each side of the equation.
-60 + 60 + 12x = -60 + 60 + 12x

Combine like terms: -60 + 60 = 0
0 + 12x = -60 + 60 + 12x
12x = -60 + 60 + 12x

Combine like terms: -60 + 60 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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