3(4x-20)=2x+100

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Solution for 3(4x-20)=2x+100 equation: 



3(4x-20)=2x+100

We move all terms to the left:

3(4x-20)-(2x+100)=0

We multiply parentheses

12x-(2x+100)-60=0

We get rid of parentheses

12x-2x-100-60=0

We add all the numbers together, and all the variables

10x-160=0

We move all terms containing x to the left, all other terms to the right

10x=160

x=160/10

x=16

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