3(4x-3)-4(6x+1)=5x+38

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Solution for 3(4x-3)-4(6x+1)=5x+38 equation:



3(4x-3)-4(6x+1)=5x+38
We move all terms to the left:
3(4x-3)-4(6x+1)-(5x+38)=0
We multiply parentheses
12x-24x-(5x+38)-9-4=0
We get rid of parentheses
12x-24x-5x-38-9-4=0
We add all the numbers together, and all the variables
-17x-51=0
We move all terms containing x to the left, all other terms to the right
-17x=51
x=51/-17
x=-3

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