3(4x-3)-4(6x+1)=5x+38

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Solution for 3(4x-3)-4(6x+1)=5x+38 equation: 



3(4x-3)-4(6x+1)=5x+38

We move all terms to the left:

3(4x-3)-4(6x+1)-(5x+38)=0

We multiply parentheses

12x-24x-(5x+38)-9-4=0

We get rid of parentheses

12x-24x-5x-38-9-4=0

We add all the numbers together, and all the variables

-17x-51=0

We move all terms containing x to the left, all other terms to the right

-17x=51

x=51/-17

x=-3

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