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3(4x-3)=2x-5(3-x)=2
We move all terms to the left:
3(4x-3)-(2x-5(3-x))=0
We add all the numbers together, and all the variables
3(4x-3)-(2x-5(-1x+3))=0
We multiply parentheses
12x-(2x-5(-1x+3))-9=0
We calculate terms in parentheses: -(2x-5(-1x+3)), so:We get rid of parentheses
2x-5(-1x+3)
We multiply parentheses
2x+5x-15
We add all the numbers together, and all the variables
7x-15
Back to the equation:
-(7x-15)
12x-7x+15-9=0
We add all the numbers together, and all the variables
5x+6=0
We move all terms containing x to the left, all other terms to the right
5x=-6
x=-6/5
x=-1+1/5
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