3(4x-4)=2x(3x-2)

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Solution for 3(4x-4)=2x(3x-2) equation: 



3(4x-4)=2x(3x-2)

We move all terms to the left:

3(4x-4)-(2x(3x-2))=0

We multiply parentheses

12x-(2x(3x-2))-12=0



We calculate terms in parentheses: -(2x(3x-2)), so:

2x(3x-2)

We multiply parentheses

6x^2-4x

Back to the equation:

-(6x^2-4x)



We get rid of parentheses

-6x^2+12x+4x-12=0

We add all the numbers together, and all the variables

-6x^2+16x-12=0

a = -6; b = 16; c = -12;
Δ = b2-4ac
Δ = 162-4·(-6)·(-12)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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