3(4x-4)=4(3x-4)+1

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Solution for 3(4x-4)=4(3x-4)+1 equation:


Simplifying
3(4x + -4) = 4(3x + -4) + 1

Reorder the terms:
3(-4 + 4x) = 4(3x + -4) + 1
(-4 * 3 + 4x * 3) = 4(3x + -4) + 1
(-12 + 12x) = 4(3x + -4) + 1

Reorder the terms:
-12 + 12x = 4(-4 + 3x) + 1
-12 + 12x = (-4 * 4 + 3x * 4) + 1
-12 + 12x = (-16 + 12x) + 1

Reorder the terms:
-12 + 12x = -16 + 1 + 12x

Combine like terms: -16 + 1 = -15
-12 + 12x = -15 + 12x

Add '-12x' to each side of the equation.
-12 + 12x + -12x = -15 + 12x + -12x

Combine like terms: 12x + -12x = 0
-12 + 0 = -15 + 12x + -12x
-12 = -15 + 12x + -12x

Combine like terms: 12x + -12x = 0
-12 = -15 + 0
-12 = -15

Solving
-12 = -15

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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