3(4x-40)=2(x+20)

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Solution for 3(4x-40)=2(x+20) equation:


Simplifying
3(4x + -40) = 2(x + 20)

Reorder the terms:
3(-40 + 4x) = 2(x + 20)
(-40 * 3 + 4x * 3) = 2(x + 20)
(-120 + 12x) = 2(x + 20)

Reorder the terms:
-120 + 12x = 2(20 + x)
-120 + 12x = (20 * 2 + x * 2)
-120 + 12x = (40 + 2x)

Solving
-120 + 12x = 40 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-120 + 12x + -2x = 40 + 2x + -2x

Combine like terms: 12x + -2x = 10x
-120 + 10x = 40 + 2x + -2x

Combine like terms: 2x + -2x = 0
-120 + 10x = 40 + 0
-120 + 10x = 40

Add '120' to each side of the equation.
-120 + 120 + 10x = 40 + 120

Combine like terms: -120 + 120 = 0
0 + 10x = 40 + 120
10x = 40 + 120

Combine like terms: 40 + 120 = 160
10x = 160

Divide each side by '10'.
x = 16

Simplifying
x = 16

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