3(4x-5)(3x+4)=0

Solution for 3(4x-5)(3x+4)=0 equation:

3(4x-5)(3x+4)=0

We multiply parentheses ..

3(+12x^2+16x-15x-20)=0

We multiply parentheses

36x^2+48x-45x-60=0

We add all the numbers together, and all the variables

36x^2+3x-60=0

a = 36; b = 3; c = -60;
Δ = b2-4ac
Δ = 32-4·36·(-60)
Δ = 8649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8649}=93$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-93}{2*36}=\frac{-96}{72}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+93}{2*36}=\frac{90}{72}
=1+1/4
$