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3(4x-5)+(11-2x)=43
We move all terms to the left:
3(4x-5)+(11-2x)-(43)=0
We add all the numbers together, and all the variables
3(4x-5)+(-2x+11)-43=0
We multiply parentheses
12x+(-2x+11)-15-43=0
We get rid of parentheses
12x-2x+11-15-43=0
We add all the numbers together, and all the variables
10x-47=0
We move all terms containing x to the left, all other terms to the right
10x=47
x=47/10
x=4+7/10
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