3(4x-5)+(11-2x)=43

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Solution for 3(4x-5)+(11-2x)=43 equation: 



3(4x-5)+(11-2x)=43

We move all terms to the left:

3(4x-5)+(11-2x)-(43)=0

We add all the numbers together, and all the variables

3(4x-5)+(-2x+11)-43=0

We multiply parentheses

12x+(-2x+11)-15-43=0

We get rid of parentheses

12x-2x+11-15-43=0

We add all the numbers together, and all the variables

10x-47=0

We move all terms containing x to the left, all other terms to the right

10x=47

x=47/10

x=4+7/10

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