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3(4x-5)+4=4(2x+1)-3
We move all terms to the left:
3(4x-5)+4-(4(2x+1)-3)=0
We multiply parentheses
12x-(4(2x+1)-3)-15+4=0
We calculate terms in parentheses: -(4(2x+1)-3), so:We add all the numbers together, and all the variables
4(2x+1)-3
We multiply parentheses
8x+4-3
We add all the numbers together, and all the variables
8x+1
Back to the equation:
-(8x+1)
12x-(8x+1)-11=0
We get rid of parentheses
12x-8x-1-11=0
We add all the numbers together, and all the variables
4x-12=0
We move all terms containing x to the left, all other terms to the right
4x=12
x=12/4
x=3
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