3(4x-5)+4=4(2x+1)-3

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Solution for 3(4x-5)+4=4(2x+1)-3 equation: 



3(4x-5)+4=4(2x+1)-3

We move all terms to the left:

3(4x-5)+4-(4(2x+1)-3)=0

We multiply parentheses

12x-(4(2x+1)-3)-15+4=0



We calculate terms in parentheses: -(4(2x+1)-3), so:

4(2x+1)-3

We multiply parentheses

8x+4-3

We add all the numbers together, and all the variables

8x+1

Back to the equation:

-(8x+1)



We add all the numbers together, and all the variables

12x-(8x+1)-11=0

We get rid of parentheses

12x-8x-1-11=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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