3(4x-5)-4=5(4x-7)-(x+5)

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Solution for 3(4x-5)-4=5(4x-7)-(x+5) equation: 



3(4x-5)-4=5(4x-7)-(x+5)

We move all terms to the left:

3(4x-5)-4-(5(4x-7)-(x+5))=0

We multiply parentheses

12x-(5(4x-7)-(x+5))-15-4=0



We calculate terms in parentheses: -(5(4x-7)-(x+5)), so:

5(4x-7)-(x+5)

We multiply parentheses

20x-(x+5)-35

We get rid of parentheses

20x-x-5-35

We add all the numbers together, and all the variables

19x-40

Back to the equation:

-(19x-40)



We add all the numbers together, and all the variables

12x-(19x-40)-19=0

We get rid of parentheses

12x-19x+40-19=0

We add all the numbers together, and all the variables

-7x+21=0

We move all terms containing x to the left, all other terms to the right

-7x=-21

x=-21/-7

x=+3

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