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3(4x-5)=2(11-2x)=43
We move all terms to the left:
3(4x-5)-(2(11-2x))=0
We add all the numbers together, and all the variables
3(4x-5)-(2(-2x+11))=0
We multiply parentheses
12x-(2(-2x+11))-15=0
We calculate terms in parentheses: -(2(-2x+11)), so:We get rid of parentheses
2(-2x+11)
We multiply parentheses
-4x+22
Back to the equation:
-(-4x+22)
12x+4x-22-15=0
We add all the numbers together, and all the variables
16x-37=0
We move all terms containing x to the left, all other terms to the right
16x=37
x=37/16
x=2+5/16
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