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3(4x-5)=2(3x+9)
We move all terms to the left:
3(4x-5)-(2(3x+9))=0
We multiply parentheses
12x-(2(3x+9))-15=0
We calculate terms in parentheses: -(2(3x+9)), so:We get rid of parentheses
2(3x+9)
We multiply parentheses
6x+18
Back to the equation:
-(6x+18)
12x-6x-18-15=0
We add all the numbers together, and all the variables
6x-33=0
We move all terms containing x to the left, all other terms to the right
6x=33
x=33/6
x=5+1/2
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