3(4x-5)=7(2x-2)

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Solution for 3(4x-5)=7(2x-2) equation: 



3(4x-5)=7(2x-2)

We move all terms to the left:

3(4x-5)-(7(2x-2))=0

We multiply parentheses

12x-(7(2x-2))-15=0



We calculate terms in parentheses: -(7(2x-2)), so:

7(2x-2)

We multiply parentheses

14x-14

Back to the equation:

-(14x-14)



We get rid of parentheses

12x-14x+14-15=0

We add all the numbers together, and all the variables

-2x-1=0

We move all terms containing x to the left, all other terms to the right

-2x=1

x=1/-2

x=-1/2

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