3(4x-5)=7(x-4)+12

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Solution for 3(4x-5)=7(x-4)+12 equation:


Simplifying
3(4x + -5) = 7(x + -4) + 12

Reorder the terms:
3(-5 + 4x) = 7(x + -4) + 12
(-5 * 3 + 4x * 3) = 7(x + -4) + 12
(-15 + 12x) = 7(x + -4) + 12

Reorder the terms:
-15 + 12x = 7(-4 + x) + 12
-15 + 12x = (-4 * 7 + x * 7) + 12
-15 + 12x = (-28 + 7x) + 12

Reorder the terms:
-15 + 12x = -28 + 12 + 7x

Combine like terms: -28 + 12 = -16
-15 + 12x = -16 + 7x

Solving
-15 + 12x = -16 + 7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7x' to each side of the equation.
-15 + 12x + -7x = -16 + 7x + -7x

Combine like terms: 12x + -7x = 5x
-15 + 5x = -16 + 7x + -7x

Combine like terms: 7x + -7x = 0
-15 + 5x = -16 + 0
-15 + 5x = -16

Add '15' to each side of the equation.
-15 + 15 + 5x = -16 + 15

Combine like terms: -15 + 15 = 0
0 + 5x = -16 + 15
5x = -16 + 15

Combine like terms: -16 + 15 = -1
5x = -1

Divide each side by '5'.
x = -0.2

Simplifying
x = -0.2

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