3(4x-5)=9x+18

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Solution for 3(4x-5)=9x+18 equation: 



3(4x-5)=9x+18

We move all terms to the left:

3(4x-5)-(9x+18)=0

We multiply parentheses

12x-(9x+18)-15=0

We get rid of parentheses

12x-9x-18-15=0

We add all the numbers together, and all the variables

3x-33=0

We move all terms containing x to the left, all other terms to the right

3x=33

x=33/3

x=11

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