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3(4x-6)+3(12-x)=15(x-1
We move all terms to the left:
3(4x-6)+3(12-x)-(15(x-1)=0
We add all the numbers together, and all the variables
3(4x-6)+3(-1x+12)-(15(x-1)=0
We multiply parentheses
12x-3x-(15(x-1)-18+36=0
We add all the numbers together, and all the variables
9x-(15(x-1)-18+36=0
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