3(4x-6)+3x+8=-4(2x-4)

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Solution for 3(4x-6)+3x+8=-4(2x-4) equation: 



3(4x-6)+3x+8=-4(2x-4)

We move all terms to the left:

3(4x-6)+3x+8-(-4(2x-4))=0

We add all the numbers together, and all the variables

3x+3(4x-6)-(-4(2x-4))+8=0

We multiply parentheses

3x+12x-(-4(2x-4))-18+8=0



We calculate terms in parentheses: -(-4(2x-4)), so:

-4(2x-4)

We multiply parentheses

-8x+16

Back to the equation:

-(-8x+16)



We add all the numbers together, and all the variables

15x-(-8x+16)-10=0

We get rid of parentheses

15x+8x-16-10=0

We add all the numbers together, and all the variables

23x-26=0

We move all terms containing x to the left, all other terms to the right

23x=26

x=26/23

x=1+3/23

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