3(4x-7)=10(x-5)

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Solution for 3(4x-7)=10(x-5) equation: 



3(4x-7)=10(x-5)

We move all terms to the left:

3(4x-7)-(10(x-5))=0

We multiply parentheses

12x-(10(x-5))-21=0



We calculate terms in parentheses: -(10(x-5)), so:

10(x-5)

We multiply parentheses

10x-50

Back to the equation:

-(10x-50)



We get rid of parentheses

12x-10x+50-21=0

We add all the numbers together, and all the variables

2x+29=0

We move all terms containing x to the left, all other terms to the right

2x=-29

x=-29/2

x=-14+1/2

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