3(4x-7)=19(x+5)

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Solution for 3(4x-7)=19(x+5) equation: 



3(4x-7)=19(x+5)

We move all terms to the left:

3(4x-7)-(19(x+5))=0

We multiply parentheses

12x-(19(x+5))-21=0



We calculate terms in parentheses: -(19(x+5)), so:

19(x+5)

We multiply parentheses

19x+95

Back to the equation:

-(19x+95)



We get rid of parentheses

12x-19x-95-21=0

We add all the numbers together, and all the variables

-7x-116=0

We move all terms containing x to the left, all other terms to the right

-7x=116

x=116/-7

x=-16+4/7

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