3(4x2+8x-5)=4x(3x+2)

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Solution for 3(4x2+8x-5)=4x(3x+2) equation: 



3(4x^2+8x-5)=4x(3x+2)

We move all terms to the left:

3(4x^2+8x-5)-(4x(3x+2))=0

We multiply parentheses

12x^2+24x-(4x(3x+2))-15=0



We calculate terms in parentheses: -(4x(3x+2)), so:

4x(3x+2)

We multiply parentheses

12x^2+8x

Back to the equation:

-(12x^2+8x)



We get rid of parentheses

12x^2-12x^2+24x-8x-15=0

We add all the numbers together, and all the variables

16x-15=0

We move all terms containing x to the left, all other terms to the right

16x=15

x=15/16

x=15/16

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