3(4y+)=6(1-y)

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Solution for 3(4y+)=6(1-y) equation: 



3(4y+)=6(1-y)

We move all terms to the left:

3(4y+)-(6(1-y))=0

We add all the numbers together, and all the variables

3(+4y)-(6(-1y+1))=0

We multiply parentheses

12y-(6(-1y+1))=0



We calculate terms in parentheses: -(6(-1y+1)), so:

6(-1y+1)

We multiply parentheses

-6y+6

Back to the equation:

-(-6y+6)



We get rid of parentheses

12y+6y-6=0

We add all the numbers together, and all the variables

18y-6=0

We move all terms containing y to the left, all other terms to the right

18y=6

y=6/18

y=1/3

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