3(4y+-5)=-3

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Solution for 3(4y+-5)=-3 equation: 



3(4y+-5)=-3

We move all terms to the left:

3(4y+-5)-(-3)=0

We add all the numbers together, and all the variables

3(4y-5)-(-3)=0

We add all the numbers together, and all the variables

3(4y-5)+3=0

We multiply parentheses

12y-15+3=0

We add all the numbers together, and all the variables

12y-12=0

We move all terms containing y to the left, all other terms to the right

12y=12

y=12/12

y=1

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