3(4y+-7)=15

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Solution for 3(4y+-7)=15 equation: 



3(4y+-7)=15

We move all terms to the left:

3(4y+-7)-(15)=0

We add all the numbers together, and all the variables

3(4y-7)-15=0

We multiply parentheses

12y-21-15=0

We add all the numbers together, and all the variables

12y-36=0

We move all terms containing y to the left, all other terms to the right

12y=36

y=36/12

y=3

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