3(4y+2)-12=18

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Solution for 3(4y+2)-12=18 equation: 



3(4y+2)-12=18

We move all terms to the left:

3(4y+2)-12-(18)=0

We add all the numbers together, and all the variables

3(4y+2)-30=0

We multiply parentheses

12y+6-30=0

We add all the numbers together, and all the variables

12y-24=0

We move all terms containing y to the left, all other terms to the right

12y=24

y=24/12

y=2

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