3(4y+3)+5(2-y)-2(3-2y)=2

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Solution for 3(4y+3)+5(2-y)-2(3-2y)=2 equation: 



3(4y+3)+5(2-y)-2(3-2y)=2

We move all terms to the left:

3(4y+3)+5(2-y)-2(3-2y)-(2)=0

We add all the numbers together, and all the variables

3(4y+3)+5(-1y+2)-2(-2y+3)-2=0

We multiply parentheses

12y-5y+4y+9+10-6-2=0

We add all the numbers together, and all the variables

11y+11=0

We move all terms containing y to the left, all other terms to the right

11y=-11

y=-11/11

y=-1

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