3(4y+5)=21

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Solution for 3(4y+5)=21 equation: 



3(4y+5)=21

We move all terms to the left:

3(4y+5)-(21)=0

We multiply parentheses

12y+15-21=0

We add all the numbers together, and all the variables

12y-6=0

We move all terms containing y to the left, all other terms to the right

12y=6

y=6/12

y=1/2

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