3(4y-1)=11+2(y-3)

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Solution for 3(4y-1)=11+2(y-3) equation: 



3(4y-1)=11+2(y-3)

We move all terms to the left:

3(4y-1)-(11+2(y-3))=0

We multiply parentheses

12y-(11+2(y-3))-3=0



We calculate terms in parentheses: -(11+2(y-3)), so:

11+2(y-3)

determiningTheFunctionDomain
2(y-3)+11

We multiply parentheses

2y-6+11

We add all the numbers together, and all the variables

2y+5

Back to the equation:

-(2y+5)



We get rid of parentheses

12y-2y-5-3=0

We add all the numbers together, and all the variables

10y-8=0

We move all terms containing y to the left, all other terms to the right

10y=8

y=8/10

y=4/5

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