3(4y-1)=2(5y+.50)

Solution for 3(4y-1)=2(5y+.50) equation:

3(4y-1)=2(5y+.50)

We move all terms to the left:

3(4y-1)-(2(5y+.50))=0

We add all the numbers together, and all the variables

3(4y-1)-(2(5y+0.5))=0

We multiply parentheses

12y-(2(5y+0.5))-3=0


We calculate terms in parentheses: -(2(5y+0.5)), so:

2(5y+0.5)

We multiply parentheses

10y+1

Back to the equation:

-(10y+1)


We get rid of parentheses

12y-10y-1-3=0

We add all the numbers together, and all the variables

2y-4=0

We move all terms containing y to the left, all other terms to the right

2y=4

y=4/2

y=2