3(4y-1)=2(5y+1/2

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Solution for 3(4y-1)=2(5y+1/2 equation: 



3(4y-1)=2(5y+1/2

We move all terms to the left:

3(4y-1)-(2(5y+1/2)=0

We add all the numbers together, and all the variables

3(4y-1)-(2(+5y+1/2)=0

We multiply parentheses

12y-(2(+5y+1/2)-3=0

We multiply all the terms by the denominator


12y*2)-3-(2(+5y+1=0

Wy multiply elements

24y^2=0

a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{48}=0$

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