3(4y-2)+11=25-(6y-2)

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Solution for 3(4y-2)+11=25-(6y-2) equation:



3(4y-2)+11=25-(6y-2)
We move all terms to the left:
3(4y-2)+11-(25-(6y-2))=0
We multiply parentheses
12y-(25-(6y-2))-6+11=0
We calculate terms in parentheses: -(25-(6y-2)), so:
25-(6y-2)
determiningTheFunctionDomain -(6y-2)+25
We get rid of parentheses
-6y+2+25
We add all the numbers together, and all the variables
-6y+27
Back to the equation:
-(-6y+27)
We add all the numbers together, and all the variables
12y-(-6y+27)+5=0
We get rid of parentheses
12y+6y-27+5=0
We add all the numbers together, and all the variables
18y-22=0
We move all terms containing y to the left, all other terms to the right
18y=22
y=22/18
y=1+2/9

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