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3(4y-2)+12=9y-3
We move all terms to the left:
3(4y-2)+12-(9y-3)=0
We multiply parentheses
12y-(9y-3)-6+12=0
We get rid of parentheses
12y-9y+3-6+12=0
We add all the numbers together, and all the variables
3y+9=0
We move all terms containing y to the left, all other terms to the right
3y=-9
y=-9/3
y=-3
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