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3(4y-2)-(5y-8)=8-(2y+3)
We move all terms to the left:
3(4y-2)-(5y-8)-(8-(2y+3))=0
We multiply parentheses
12y-(5y-8)-(8-(2y+3))-6=0
We get rid of parentheses
12y-5y-(8-(2y+3))+8-6=0
We calculate terms in parentheses: -(8-(2y+3)), so:We add all the numbers together, and all the variables
8-(2y+3)
determiningTheFunctionDomain -(2y+3)+8
We get rid of parentheses
-2y-3+8
We add all the numbers together, and all the variables
-2y+5
Back to the equation:
-(-2y+5)
7y-(-2y+5)+2=0
We get rid of parentheses
7y+2y-5+2=0
We add all the numbers together, and all the variables
9y-3=0
We move all terms containing y to the left, all other terms to the right
9y=3
y=3/9
y=1/3
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