3(4y-2)-7=2(3y-7)-3

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Solution for 3(4y-2)-7=2(3y-7)-3 equation: 



3(4y-2)-7=2(3y-7)-3

We move all terms to the left:

3(4y-2)-7-(2(3y-7)-3)=0

We multiply parentheses

12y-(2(3y-7)-3)-6-7=0



We calculate terms in parentheses: -(2(3y-7)-3), so:

2(3y-7)-3

We multiply parentheses

6y-14-3

We add all the numbers together, and all the variables

6y-17

Back to the equation:

-(6y-17)



We add all the numbers together, and all the variables

12y-(6y-17)-13=0

We get rid of parentheses

12y-6y+17-13=0

We add all the numbers together, and all the variables

6y+4=0

We move all terms containing y to the left, all other terms to the right

6y=-4

y=-4/6

y=-2/3

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