3(4y-2)=-6+12y

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Solution for 3(4y-2)=-6+12y equation:


Simplifying
3(4y + -2) = -6 + 12y

Reorder the terms:
3(-2 + 4y) = -6 + 12y
(-2 * 3 + 4y * 3) = -6 + 12y
(-6 + 12y) = -6 + 12y

Add '6' to each side of the equation.
-6 + 6 + 12y = -6 + 6 + 12y

Combine like terms: -6 + 6 = 0
0 + 12y = -6 + 6 + 12y
12y = -6 + 6 + 12y

Combine like terms: -6 + 6 = 0
12y = 0 + 12y
12y = 12y

Add '-12y' to each side of the equation.
12y + -12y = 12y + -12y

Combine like terms: 12y + -12y = 0
0 = 12y + -12y

Combine like terms: 12y + -12y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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